document.write( "Question 1206450: solve for x: \r
\n" ); document.write( "\n" ); document.write( "log 2 (x-1) - log 2 (x+2) + log2 (x+3) = 2\r
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Algebra.Com's Answer #843943 by ikleyn(52835) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "The given equation is equivalent to\r\n" );
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document.write( "     = \r\n" );
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document.write( "plus the condition that each factor in parentheses is positive number.\r\n" );
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document.write( "From it, we get\r\n" );
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document.write( "    (x-1)*(x+3) = 4*(x+2)\r\n" );
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document.write( "     x^2 - x + 3x - 3 = 4x + 8\r\n" );
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document.write( "     x^2 - 2x - 11 = 0\r\n" );
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document.write( "Apply the quadratic formula and find the roots\r\n" );
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document.write( "     =  =  =  = .\r\n" );
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document.write( "One root is x =  = 4.4641  (rounded).\r\n" );
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document.write( "Another root is   = -2.4641  (rounded).\r\n" );
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document.write( "Only positive root is the solution to the original equation, since (x-1) is also positive.\r\n" );
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document.write( "The negative root is not the solution to the original equation, since then (x-1) is negative, too.\r\n" );
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