document.write( "Question 1206447: Six story books, A, B, C, D, E, and F were arranged on a shelf randomly. If A and B were not placed together, what is the probability that there was one book between A and B? \n" ); document.write( "
Algebra.Com's Answer #843939 by greenestamps(13198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The number of ways the 6 books can be arranged on the shelf is 6! = 720. \n" ); document.write( "For the number of ways the two books A and B can be together, consider them as a single unit. Then there are 5 things to be arranged on the shelf, in 5! = 120 different ways; and within the AB pair those two can be arranged in 2 different ways. So the number of ways the books can be arranged with A and B together is 120*2 = 240. \n" ); document.write( "So the number of ways in which the books can be arranged with A and B NOT together is 720-240 = 480. \n" ); document.write( "For the case where there is exactly one book between A and B.... \n" ); document.write( "(1) There are 4 places in the arrangement of the 6 books where there is exactly one book between A and B -- positions 1 to 3, 2 to 4, 3 to 5, and 4 to 6. \n" ); document.write( "(2) The two books A and B can be in either of 2 different orders. \n" ); document.write( "(3) The other four books can be arranged in 4! = 24 different ways. \n" ); document.write( "The number of ways for there to be one book between A and B is 4*2*24 = 192. \n" ); document.write( "So the probability that there is one book between A and B, given that A and B are not together, is 192/480 = 2/5. \n" ); document.write( "ANSWER: 2/5 \n" ); document.write( " \n" ); document.write( " |