document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1112125>Question 1112125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the compound interest for 2nd year is 250, find the compound interest for 3rd year, interest being 12% per annum. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #843929 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=843929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> CI of the 2nd year = Rs. 250 \r<BR>\n" );
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document.write( " CI of the 3rd year will be = CI of 2nd year+ 12% interest on CI of 2nd year\r<BR>\n" );
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document.write( "CI of 3rd year = 250 + 250 × 0.12 = Rs. 280\r<BR>\n" );
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