document.write( "Question 116023: How do I identify this equation as a circle and to specify the center and the radius?\r
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document.write( "I worked on the equation and made it into the (x-h)^2+(y-k)^2=r form:\r
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document.write( "but I don't understand how the radius can be zero. \n" );
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Algebra.Com's Answer #84392 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! x^2+y^2-8x+4y+20=0 \n" ); document.write( "-------- \n" ); document.write( "x^2-8x+16 + y^2+4y+4 = -20 + 16 +4 \n" ); document.write( "(x-4)^2 + (x+2)^2 = 0 \n" ); document.write( "----------------------- \n" ); document.write( "This is not a circle as you said. \n" ); document.write( "----------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |