document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1071930>Question 1071930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Frame Masters, Inc., recently purchased $5500 worth of new equipment in order to offer a new style of eyeglass frame. The marketing department of Frame Masters estimates that the cost of producing this new frame is $18 and that the frame will be sold to stores for $38. Find the number of frames that must be sold in order to break even </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #843890 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=843890\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Let x as the number of frames sold\r<BR>\n" );
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document.write( "R(x)  the revenue from selling x frames\r<BR>\n" );
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document.write( "C(x) as the total cost of producing and selling x frames\r<BR>\n" );
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document.write( "Revenue = 38x\r<BR>\n" );
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document.write( "Cost = 5000+18x\r<BR>\n" );
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document.write( "For break even\r<BR>\n" );
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document.write( "38x = 5000+18x\r<BR>\n" );
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document.write( "20x = 5000\r<BR>\n" );
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document.write( "x= 275\r<BR>\n" );
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document.write( " Sell 275 frames to break even.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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