document.write( "Question 1206417: Question: Find an equation for a circle with center ( ―2, 3), tangent (touching at one point) to the y-axis.\r
\n" ); document.write( "\n" ); document.write( "My Attempt:
\n" ); document.write( "Formula for a circle: (x-h)^2+(y-k)^2=r^2
\n" ); document.write( "(x+2)^2+(y-3)^2=r^2
\n" ); document.write( "Would this be the final equation? And if I am given a specific point that passes through the y-axis I would substitute that given ordered pair into x and y and solve for r^2, then replace it back into the original equation correct?
\n" ); document.write( "For example: Center = (-2,3) passes through (3,7)
\n" ); document.write( "(3+2)^2+(7-3)^2=r^2
\n" ); document.write( "sqrt(41)=r
\n" ); document.write( "Final equation = (x+2)^2+(y-3)^2=sqrt(41)
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Algebra.Com's Answer #843877 by MathLover1(20855)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Formula for a circle: \r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\".....center ( \"-2\", \"3\")\r
\n" ); document.write( "\n" ); document.write( "The circle is \"tangent\" to the \"y\"-axis (we know that tangent refers to a line that \"touches\" something at exactly one point, we want the circle to have a radius that will make it just big enough to reach the \"y\"-axis), hence its radius \"r=x-coordinate=-2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2%2B%28y-3%29%5E2=%28-2%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2%2B%28y-3%29%5E2=4\"\r
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