document.write( "Question 1206395: A cross section of a reflector of a television satellite dish is a parabola that measures 5 ft across with a depth of 2 ft. How far from the vertex should the receiving antenna be placed?\r
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Algebra.Com's Answer #843835 by ikleyn(52855)\"\" \"About 
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\n" ); document.write( "A cross section of a reflector of a television satellite dish is a parabola
\n" ); document.write( "that measures 5 ft across with a depth of 2 ft. How far from the vertex should the receiving antenna be placed?
\n" ); document.write( "A. 0.3125 ft
\n" ); document.write( "B. 0.78125 ft
\n" ); document.write( "C. 0.2500 ft
\n" ); document.write( "D. 1.25 ft
\n" ); document.write( "E. 0.625 ft
\n" ); document.write( "F. 1.8125 ft
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document.write( "Place the origin of the coordinate system at vertex of the parabola.\r\n" );
document.write( "Use the vertex form equation of this parabola \r\n" );
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document.write( "    y = \"ax%5E2\".        (1)\r\n" );
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document.write( "At x = 2.5 ft, we are given y = 2 ft.  So, this vertex equation takes the form\r\n" );
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document.write( "    2 = \"a%2A2.5%5E2\",  which gives  a = \"2%2F2.5%5E2\" = \"2%2F6.25\" = \"8%2F25\".\r\n" );
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document.write( "So, equation (1) is  \r\n" );
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document.write( "    y = \"%288%2F25%29%2Ax%5E2\".    (2)\r\n" );
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document.write( "For the parabola with equation y = \"ax%5E2\",  the distance from the vertex to the focus is\r\n" );
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document.write( "    f = \"1%2F4a\".\r\n" );
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document.write( "In our case, the distance from the vertex to the focus is   \"1%2F%284%2A%288%2F25%29%29\" = \"25%2F32\" cm = 0.78125 ft.\r\n" );
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document.write( "ANSWER.  The distance from the vertex to the focus, where the filament should be placed, is 0.78125 ft.  \r\n" );
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document.write( "         Option (B).\r\n" );
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