document.write( "Question 1168236: Write the equation of a circle that satisfies the given conditions:
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document.write( "(a) the center is at (1, -3) and the circle passes through (-3, 5).
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document.write( "(b) the line segment joining A (0, 0), and B (6, -8) is a diameter.
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document.write( "(c) the circle is tangent to y-axis, and the center is at (5, 3) \n" );
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Algebra.Com's Answer #843805 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Write the equation of a circle that satisfies the given conditions: \n" ); document.write( "(a) the center is at (1, -3) and the circle passes through (-3, 5). \n" ); document.write( "(b) the line segment joining A (0, 0), and B (6, -8) is a diameter. \n" ); document.write( "(c) the circle is tangent to y-axis, and the center is at (5, 3)\r \n" ); document.write( "\n" ); document.write( "(a) the center is at (1, -3) and the circle passes through (-3, 5).\r \n" ); document.write( "\n" ); document.write( "Find radius by distance formula.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r= sqrt(80)\r \n" ); document.write( "\n" ); document.write( "=4sqrt(5)\r \n" ); document.write( "\n" ); document.write( "Now we have the radius, r, and the center (ℎ,k)~(1,-3) and radius 4sqrt(5) \n" ); document.write( " We can plug these values into the general equation of a circle:\r \n" ); document.write( "\n" ); document.write( "(x-1)^2+(y+3)^2= (4sqrt(5))^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-1)^2+(y+3)^2= 80 \n" ); document.write( " \n" ); document.write( " |