document.write( "Question 1168235: The circles (x+1)^2+(y-1)^2=9 and (x-3)^2+(y+1)^2=9 are overlapped. Find the point of intersections of the circles. \n" ); document.write( "
Algebra.Com's Answer #843803 by mananth(16946)\"\" \"About 
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The circles (x+1)^2+(y-1)^2=9 and (x-3)^2+(y+1)^2=9 are overlapped. Find the point of intersections of the circles.\r
\n" ); document.write( "\n" ); document.write( "Since they intersect, there must be common points\r
\n" ); document.write( "\n" ); document.write( "we equate both\r
\n" ); document.write( "\n" ); document.write( " (x+1)^2+(y-1)^2=9 = (x-3)^2+(y+1)^2\r
\n" ); document.write( "\n" ); document.write( "x^2+2x+1+y^2-2y+1 =x^2-6x+9+y^2+2y+1\r
\n" ); document.write( "\n" ); document.write( "2x-2y+1 = -6x+2y+9\r
\n" ); document.write( "\n" ); document.write( "8x-4y=8\r
\n" ); document.write( "\n" ); document.write( "y=2x-2\r
\n" ); document.write( "\n" ); document.write( "Circle equation
\n" ); document.write( "x^2+2x+1+y^2-2y+1 =9\r
\n" ); document.write( "\n" ); document.write( "x^2+2x+y^2-2y =7\r
\n" ); document.write( "\n" ); document.write( "substitute y =2x-2\r
\n" ); document.write( "\n" ); document.write( "x^2+2x+(2x-2)^2-2(2x-2)=7\r
\n" ); document.write( "\n" ); document.write( "x^2+2x+4x^2-8x+4-4x+4=7\r
\n" ); document.write( "\n" ); document.write( "5x^2-10x+1=0
\n" ); document.write( "Solve for x by formula method to get value of x (two values )
\n" ); document.write( "substitute x in y=2x-2 to get y.\r
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