document.write( "Question 1206368: A telemarketer makes six phone calls per hour and is able to make a sale on 30 percent of
\n" ); document.write( "these contacts. During the next two hours, find:
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\n" ); document.write( "b. The probability of making no sales.
\n" ); document.write( "c. The probability of making exactly two sales.
\n" ); document.write( "d. The mean number of sales in the two-hour period. \n" ); document.write( "

Algebra.Com's Answer #843786 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "A telemarketer makes six phone calls per hour and is able to make a sale
\n" ); document.write( "on 30% of these contacts. During the next two hours. Find:
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\n" ); document.write( "\n" ); document.write( "Assuming that the next 2 hours he/she works at the same intensity
\n" ); document.write( "(does not have a coffee break/(lunch break) and continues his working hours),
\n" ); document.write( "in the next two hours, he/she makes 12 phone calls.\r
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document.write( "a) The probability of exactly making four sales \r\n" );
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document.write( "   Ans: 12C4*0.3^4*0.7^(12-4) = 495*0.3^4*0.7^8 = 0.2311 (rounded).\r\n" );
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document.write( "b) The probability of making no sales.\r\n" );
document.write( "   Ans: 0.7^12 = 0.01384 (rounded).\r\n" );
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document.write( "c) The probability of exactly making two sales.\r\n" );
document.write( "   Ans: 12C2*0.3^2*0.7^(12-2) = 66*0.3^2*0.7^10 = 0.1678  (rounded).\r\n" );
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document.write( "d) The mean number of sales within the two-hour period.\r\n" );
document.write( "   mean = np = 12*0.3 = 3.6 sales\r\n" );
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