document.write( "Question 1125543: The volume of ice-cream in the cone is half the volume of the cone. The cone has a 3 cm radius and height of 14 cm. What is the depth of the ice-cream, correct to 2 decimal places? \n" ); document.write( "
Algebra.Com's Answer #843760 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "The volume of ice-cream in the cone is half the volume of the cone.
\n" ); document.write( "The cone has a 3 cm radius and height of 14 cm. What is the depth of
\n" ); document.write( "the ice-cream, correct to 2 decimal places?
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\n" ); document.write( "\n" ); document.write( "In this problem, there is no need to calculate volumes of the cones.\r
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document.write( "The cone volumes ratio is 2 (the greater to the smaller);\r\n" );
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document.write( "hence, from similarity of the cones, the ratio of heights (greater to smaller) is  \"root%283%2C2%29\" = 1.26  (rounded).\r\n" );
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document.write( "So, the depth of the ice-cream is  \"14%2F1.26\" = 11.11 cm.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved,  as simple and in a way as it should be done.\r
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\n" ); document.write( "\n" ); document.write( "By the way, the given radius of the greater cone of 3 cm is irrelevant.
\n" ); document.write( "This value is excessive, is not necessary, and the problem can be solved without it . . . \r
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\n" ); document.write( "\n" ); document.write( "The answer to the question does not depend on the radius of the greater cone
\n" ); document.write( "and is the same for any other value of the radius of the greater cone.\r
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