document.write( "Question 1125543: The volume of ice-cream in the cone is half the volume of the cone. The cone has a 3 cm radius and height of 14 cm. What is the depth of the ice-cream, correct to 2 decimal places? \n" ); document.write( "
Algebra.Com's Answer #843758 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "From fig:\r
\n" ); document.write( "\n" ); document.write( "r/h = 3/14\r
\n" ); document.write( "\n" ); document.write( "r=3h/14\r
\n" ); document.write( "\n" ); document.write( "Volume of cone = 1/3 * pi*r^2*h\r
\n" ); document.write( "\n" ); document.write( "Plug values r=3 and h=14
\n" ); document.write( "V=132 in^3\r
\n" ); document.write( "\n" ); document.write( "Icecream is half volume of cone\r
\n" ); document.write( "\n" ); document.write( "V ice cream =66 in^3\r
\n" ); document.write( "\n" ); document.write( "r= 3h/14
\n" ); document.write( "substitute in cone volume formula\r
\n" ); document.write( "\n" ); document.write( "66= (1/3)*(22/7)*(3h/14)^2*h\r
\n" ); document.write( "\n" ); document.write( "198*7/22 = (9h^2/196)*h\r
\n" ); document.write( "\n" ); document.write( "63= (9h^2/196)*h\r
\n" ); document.write( "\n" ); document.write( "63*196/9 = h^3\r
\n" ); document.write( "\n" ); document.write( "7*196=h^3
\n" ); document.write( "h=11.11 cm height/depth of ice cream\r
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