document.write( "Question 1206350: A sample of 75 people yielded the following information about their health insurance.\r
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document.write( "33 people with managed care plan
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document.write( "27 people with traditional insurance
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document.write( "15 people with no insurance\r
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document.write( "Two people who provided information for the table were randomly selected, without replacement. Determine the probability that:\r
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document.write( "A. Neither had traditional insurance. \n" );
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Algebra.Com's Answer #843744 by Theo(13342)![]() ![]() You can put this solution on YOUR website! probability of the first person selected not having traditional insurance is 15/75.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of the second person selected not having traditional insurance is 14/74.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability that both selected didn't have traditional insurance would be 15/75 * 14/74 = 210 / 5550\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this simplifies to 7 / 185.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "as a decimal, this is equal to .03784 when rounded to 5 decimal places.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |