document.write( "Question 1027688: The area of triangle ABC is trisected by two segments parallel to base BC. The longer of these segments is 24 cm. What is the length of base BC? Express your answer in simplest radical form. \n" ); document.write( "
Algebra.Com's Answer #843708 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
The area of triangle ABC is trisected by two segments parallel to base BC. The longer of these segments is 24 cm. What is the length of base BC? Express your answer in simplest radical form.\r
\n" ); document.write( "\n" ); document.write( "Triangle ABC znd triangle AFG are similar\r
\n" ); document.write( "\n" ); document.write( "Triangle ABC /triangle AFG = BC^2/FG^2\r
\n" ); document.write( "\n" ); document.write( "3/2 = BC^2/FG^2\r
\n" ); document.write( "\n" ); document.write( "3/2 = BC^2/12^2\r
\n" ); document.write( "\n" ); document.write( "BC^2= 3/2 * 12^2\r
\n" ); document.write( "\n" ); document.write( "BC = sqrt( 3/2*12^2)\r
\n" ); document.write( "\n" ); document.write( "BC = 12sqrt(6)\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );