document.write( "Question 1130221: Use a model to determine the amount owed on a loan of $5,000 with simple interest of 4.25%. The model was A=5000+5000(0.0425t), where A is the amount (total principal plus interest) required to repay a loan, and t is the time, in years.\r
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document.write( "What is the slope of this model? Include units in your answer.\r
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document.write( "How long would it take for the loan amount to reach $7,000? Round to the nearest tenth. \n" );
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Algebra.Com's Answer #843705 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Use a model to determine the amount owed on a loan of $5,000 with simple interest of 4.25%. The model was A=5000+5000(0.0425t), where A is the amount (total principal plus interest) required to repay a loan, and t is the time, in years. \n" ); document.write( "What is the slope of this model? Include units in your answer. \n" ); document.write( "How long would it take for the loan amount to reach $7,000? Round to the nearest tenth.\r \n" ); document.write( "\n" ); document.write( "A=5000+5000(0.0425t)\r \n" ); document.write( "\n" ); document.write( "A= 212.5t +5000\r \n" ); document.write( "\n" ); document.write( "compare with y=mx+c\r \n" ); document.write( "\n" ); document.write( "Slope = m= 212.5\r \n" ); document.write( "\n" ); document.write( "A=7000\r \n" ); document.write( "\n" ); document.write( "A= 212.5t +5000\r \n" ); document.write( "\n" ); document.write( "7000 = 212.50t+5000\r \n" ); document.write( "\n" ); document.write( "2000/212.50=t\r \n" ); document.write( "\n" ); document.write( "t= 9.412 years \n" ); document.write( " |