document.write( "Question 1130221: Use a model to determine the amount owed on a loan of $5,000 with simple interest of 4.25%. The model was A=5000+5000(0.0425t), where A is the amount (total principal plus interest) required to repay a loan, and t is the time, in years.\r
\n" ); document.write( "\n" ); document.write( "What is the slope of this model? Include units in your answer.\r
\n" ); document.write( "\n" ); document.write( "How long would it take for the loan amount to reach $7,000? Round to the nearest tenth.
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Algebra.Com's Answer #843705 by mananth(16946)\"\" \"About 
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Use a model to determine the amount owed on a loan of $5,000 with simple interest of 4.25%. The model was A=5000+5000(0.0425t), where A is the amount (total principal plus interest) required to repay a loan, and t is the time, in years.
\n" ); document.write( "What is the slope of this model? Include units in your answer.
\n" ); document.write( "How long would it take for the loan amount to reach $7,000? Round to the nearest tenth.\r
\n" ); document.write( "\n" ); document.write( "A=5000+5000(0.0425t)\r
\n" ); document.write( "\n" ); document.write( "A= 212.5t +5000\r
\n" ); document.write( "\n" ); document.write( "compare with y=mx+c\r
\n" ); document.write( "\n" ); document.write( "Slope = m= 212.5\r
\n" ); document.write( "\n" ); document.write( "A=7000\r
\n" ); document.write( "\n" ); document.write( "A= 212.5t +5000\r
\n" ); document.write( "\n" ); document.write( "7000 = 212.50t+5000\r
\n" ); document.write( "\n" ); document.write( "2000/212.50=t\r
\n" ); document.write( "\n" ); document.write( "t= 9.412 years
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