document.write( "Question 1206328: A coin is tossed 13 times.
\n" ); document.write( "a) How many different outcomes are possible?
\n" ); document.write( " b) What is the probability of getting exactly 3 heads?
\n" ); document.write( "c) What is the probability of getting at least 2 heads?
\n" ); document.write( " d) What is the probability of getting at most 9 heads?
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Algebra.Com's Answer #843695 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
this looks like a binomial distribution type problem.\r
\n" ); document.write( "\n" ); document.write( "formula for that is:\r
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\n" ); document.write( "\n" ); document.write( "p(x) = p^x * q^(n-x) * c(n,x)\r
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\n" ); document.write( "\n" ); document.write( "c(n,x) = n! / (x! * (n-x)!)\r
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\n" ); document.write( "\n" ); document.write( "in this problem:
\n" ); document.write( "n = 13
\n" ); document.write( "x = 0 to 13
\n" ); document.write( "p = probability of heads = .5
\n" ); document.write( "q = probability of tails = .5\r
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\n" ); document.write( "\n" ); document.write( "the total probability will be equal to 1.\r
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\n" ); document.write( "\n" ); document.write( "the excel spreadsheet shown below gives you all the probabilities.\r
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\n" ); document.write( "\n" ); document.write( "your solutions are:\r
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\n" ); document.write( "\n" ); document.write( "sum of all probabilities equals 1.\r
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\n" ); document.write( "\n" ); document.write( "probability of getting exactly 3 heads equals 0.034912109.\r
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\n" ); document.write( "\n" ); document.write( "probability of getting at least 2 heads = 0.998291016.\r
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\n" ); document.write( "\n" ); document.write( "probability of getting at most 9 heads = 0.953857422.\r
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\n" ); document.write( "\n" ); document.write( "as an example of the calculations involved, we'll look at the probability of getting at least 2 heads.\r
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\n" ); document.write( "\n" ); document.write( "since the probability of getting at least 2 heads is the same as 1 minus the probability of getting less than 2 heads, and it's much easier to make two calculations rather than 12 calculations, we'll calculate 1 minus the probability of getting less than 2 heads..\r
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\n" ); document.write( "\n" ); document.write( "formula is p(x) = p^x * q^(n-x) * c(n,x).
\n" ); document.write( "c(n,x) = n! / (x! * (n-x)!)\r
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\n" ); document.write( "\n" ); document.write( "n = 13
\n" ); document.write( "p = .5
\n" ); document.write( "q = .5\r
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\n" ); document.write( "\n" ); document.write( "p(x = 0) = .5^0 * .5^13 * c(13,0) = .0001220703125.
\n" ); document.write( "p(x = 1) = .5^1 * .5^12 * c(13,1) = .0015869141.\r
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\n" ); document.write( "\n" ); document.write( "p(x = 0 to 1) = .0017089844.
\n" ); document.write( "1 minus that = .9982910156.
\n" ); document.write( "round that to 9 decimal digits (same as excel), and you get .998291016.
\n" ); document.write( "that's the same as excel provides you.\r
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\n" ); document.write( "\n" ); document.write( "the solution made use of the fact that p(x >= 2) is the same as 1 minus p(x < 2).
\n" ); document.write( "this allowed many less manual calculations to be performed.\r
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