document.write( "Question 1206316: How do you solve sin x + square root of 2 = - sin x on the interval -pi/2 < x < pi/2 \n" ); document.write( "
Algebra.Com's Answer #843664 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " sin x + square root of 2 = - sin x\r
\n" ); document.write( "\n" ); document.write( " sin x + square root of 2 + sin x=0\r
\n" ); document.write( "\n" ); document.write( "2sin x =- sqrt( 2 )\r
\n" ); document.write( "\n" ); document.write( "sin x = -sqrt(2)/2\r
\n" ); document.write( "\n" ); document.write( "sin (x)= - 1/sqrt(2)\r
\n" ); document.write( "\n" ); document.write( "the interval -pi/2 < x < pi/2\r
\n" ); document.write( "\n" ); document.write( "sine is negative in the third and fourth quadrants, find the angle in the third quadrant.\r
\n" ); document.write( "\n" ); document.write( "x =-pi/2\r
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