document.write( "Question 1206316: How do you solve sin x + square root of 2 = - sin x on the interval -pi/2 < x < pi/2 \n" ); document.write( "

Algebra.Com's Answer #843663 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"sin%28+x%29+%2B+sqrt%28+2%29+=+-+sin%28+x%29\"$ on the interval $\"-pi%2F2+%3C+x+%3C+pi%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"sin%28+x%29+%2Bsin%28+x%29++=+-+sqrt%28+2%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2sin%28+x%29++=+-+sqrt%28+2%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"sin%28+x%29++=+-+sqrt%28+2%29%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=sin%5E-1%28-+sqrt%28+2%29%2F2%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=-pi%2F4\"$
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