document.write( "Question 115899: Trudy Waterbury, a financial planner, invested a certain amount of money at 9% annual simple interest, twice that amount at 10% annual simple interest, and three times that amount at 11% annual simple interest. Find the amount invested at each rate if her total yearly income from the investments was $2790. \n" ); document.write( "
Algebra.Com's Answer #84365 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .09x+.10*2x+.11*3x=2790 \n" ); document.write( ".09x+.20x+.33x=2790 \n" ); document.write( ".62x=2790 \n" ); document.write( "x=2790/.62 \n" ); document.write( "x=$4,500 invested @ 9% \n" ); document.write( "2*4,500=9000 invested @ 10% \n" ); document.write( "3*4500=13500 invested @ 11% \n" ); document.write( "proof \n" ); document.write( ".09*4500+.1*9000+.11*13500=2790 \n" ); document.write( "405+900+1485=2790 \n" ); document.write( "2790=2790 \n" ); document.write( " \n" ); document.write( " |