document.write( "Question 115899: Trudy Waterbury, a financial planner, invested a certain amount of money at 9% annual simple interest, twice that amount at 10% annual simple interest, and three times that amount at 11% annual simple interest. Find the amount invested at each rate if her total yearly income from the investments was $2790. \n" ); document.write( "
Algebra.Com's Answer #84365 by checkley71(8403)\"\" \"About 
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.09x+.10*2x+.11*3x=2790
\n" ); document.write( ".09x+.20x+.33x=2790
\n" ); document.write( ".62x=2790
\n" ); document.write( "x=2790/.62
\n" ); document.write( "x=$4,500 invested @ 9%
\n" ); document.write( "2*4,500=9000 invested @ 10%
\n" ); document.write( "3*4500=13500 invested @ 11%
\n" ); document.write( "proof
\n" ); document.write( ".09*4500+.1*9000+.11*13500=2790
\n" ); document.write( "405+900+1485=2790
\n" ); document.write( "2790=2790
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