document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1099257>Question 1099257</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three no are in continued proportion .if mean proportional is 12 and sum of other two is 26 then find the no </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #843629 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=843629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Three no are in continued proportion .if mean proportional is 12 and sum of other two is 26 then find the numbers\r<BR>\n" );
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document.write( "a/b = b/c\r<BR>\n" );
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document.write( "b=12<BR>\n" );
document.write( "a/12=12/c\r<BR>\n" );
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document.write( "ac = 144<BR>\n" );
document.write( "a =144/c\r<BR>\n" );
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document.write( "a+c =26\r<BR>\n" );
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document.write( "substitute a\r<BR>\n" );
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document.write( "144/c +c =26\r<BR>\n" );
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document.write( "multiply equation by c\r<BR>\n" );
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document.write( "144 +c^2 = 26c\r<BR>\n" );
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document.write( "c^2-26c+144=0\r<BR>\n" );
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document.write( "c^2-26c=-144<BR>\n" );
document.write( "Add 169 to both sides\r<BR>\n" );
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document.write( "c^2-26c +169 =169- 144\r<BR>\n" );
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document.write( "(c-13)^2= 25\r<BR>\n" );
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document.write( "take the square rooton both sides\r<BR>\n" );
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document.write( "(c-13)=+ /- 5\r<BR>\n" );
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document.write( "either c-13 = 5 or c-13 = -5\r<BR>\n" );
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document.write( "c= 18 or c= 8\r<BR>\n" );
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document.write( "ac =144\r<BR>\n" );
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document.write( "a = 144/18   or 144/8\r<BR>\n" );
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document.write( "a= 8 or 18\r<BR>\n" );
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document.write( " </SPAN>\n" );
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