document.write( "Question 1206285: An urn contains 5 red balls and 8 yellow balls. If Vince chooses 10 balls at random from the urn, what is the probability that he will select 4 red balls and 6 yellow balls? Round your answer to 3 decimal places. \n" ); document.write( "
Algebra.Com's Answer #843609 by Theo(13342)\"\" \"About 
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the set contains 5 red and 8 yellow balls.\r
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\n" ); document.write( "\n" ); document.write( "i think this can be done this way.
\n" ); document.write( "p(4 red and 6 yellow) = c(5,4) * c(8,6) / c(13,10) = .4895104895.\r
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\n" ); document.write( "\n" ); document.write( "i think it can also be done this way.
\n" ); document.write( "p(4 red and 6 yellow) = 5/13 * 4/12 * 3/11 * 2/10 * 8/9 * 7/8 * 6/7 * 5/6 * 4/5 * 3/4 * c(10,4) = .4895104895.\r
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\n" ); document.write( "\n" ); document.write( "the first way is essentially the number of ways you can get your want divided by the total number of possible ways.\r
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\n" ); document.write( "\n" ); document.write( "the formula is p(4 red and 6 yellow) = c(5,4) * c(8,6) / c(13,10)\r
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\n" ); document.write( "\n" ); document.write( "that translates to:\r
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\n" ); document.write( "\n" ); document.write( "the number of ways you can get 4 red balls from 5 red balls is c(5,4).
\n" ); document.write( "the number of ways you can get 6 yellow balls from 8 yellow balls is c(8,6).
\n" ); document.write( "the number of ways you can get 4 red balls and 6 yellow balls becomes c(5,4) * c(8,6) which translates to the number of ways you can get 4 red balls times the number of ways you can get 6 yellow balls.
\n" ); document.write( "that's the numerator.
\n" ); document.write( "the number of possible ways to get 10 balls out of 13 balls is c(13,10).
\n" ); document.write( "that's the denominator.\r
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\n" ); document.write( "\n" ); document.write( "the second way looks at the probability of getting them in a specified order.\r
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\n" ); document.write( "\n" ); document.write( "that formula becomes p(4 red and 6 yellow) = 5/13 * 4/12 * 3/11 * 2/10 * 8/9 * 7/8 * 6/7 * 5/6 * 4/5 * 3/4 * c(10,4) = .4895104895.\r
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\n" ); document.write( "\n" ); document.write( "on your first draw you pick a red.
\n" ); document.write( "the probability of that is 5/13.
\n" ); document.write( "on your second draw you pick another red.
\n" ); document.write( "the probability of that is 4/12.
\n" ); document.write( "ditto until you pick the 4th ball as red.
\n" ); document.write( "starting from the 5th ball you draw, you are not looking at yellow.
\n" ); document.write( "probability of the firth ball being yellow is 8/9.
\n" ); document.write( "that's because there are 8 yellow balls left out of a total of 9 left.
\n" ); document.write( "this continues until your last draw of a yellow ball whose probability is 3/4.
\n" ); document.write( "there are 4 balls left.
\n" ); document.write( "they are RYYY
\n" ); document.write( "that's because you took our 4 red and 5 yellow for a total of 9
\n" ); document.write( "13 minus 9 = 4 balls left
\n" ); document.write( "5 red minus 4 red = 1 red left
\n" ); document.write( "8 yellow minus 5 yellow = 3 yellow left.\r
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\n" ); document.write( "\n" ); document.write( "you wind up with 10 balls that were picked in a certain order.
\n" ); document.write( "the number of ways those 10 could be ordered is c(10,4).
\n" ); document.write( "that's the number of possible ways you can arrange 4 red balls from 10 total balls.
\n" ); document.write( "the other number of ways those 10 could be ordered is c(10,6).
\n" ); document.write( "that's the number of possible ways you can arrange 6 yellow balls from 10 total balls.
\n" ); document.write( "c(10,4) = 210
\n" ); document.write( "c(10,6) also = 210.\r
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\n" ); document.write( "\n" ); document.write( "two different ways get you the same answer which at least confirms the ways are consistent.\r
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\n" ); document.write( "\n" ); document.write( "to see how each formula works, you can work a different problems where the numbers are small enough that you can show each possible say separately.
\n" ); document.write( "i did that with this problem and it confirms both methods are good.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that the probability is equal to .4895104895.\r
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\n" ); document.write( "\n" ); document.write( "round that to 3 decimal places to get .490 which is the same as .49.
\n" ); document.write( "even though .49 is the same as .490, you should probably show it as .490 just to indicate that you rounded to 3 decimal places, and not 2.\r
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