document.write( "Question 1206285: An urn contains 5 red balls and 8 yellow balls. If Vince chooses 10 balls at random from the urn, what is the probability that he will select 4 red balls and 6 yellow balls? Round your answer to 3 decimal places. \n" ); document.write( "
Algebra.Com's Answer #843609 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the set contains 5 red and 8 yellow balls.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i think this can be done this way. \n" ); document.write( "p(4 red and 6 yellow) = c(5,4) * c(8,6) / c(13,10) = .4895104895.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i think it can also be done this way. \n" ); document.write( "p(4 red and 6 yellow) = 5/13 * 4/12 * 3/11 * 2/10 * 8/9 * 7/8 * 6/7 * 5/6 * 4/5 * 3/4 * c(10,4) = .4895104895.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first way is essentially the number of ways you can get your want divided by the total number of possible ways.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula is p(4 red and 6 yellow) = c(5,4) * c(8,6) / c(13,10)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that translates to:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the number of ways you can get 4 red balls from 5 red balls is c(5,4). \n" ); document.write( "the number of ways you can get 6 yellow balls from 8 yellow balls is c(8,6). \n" ); document.write( "the number of ways you can get 4 red balls and 6 yellow balls becomes c(5,4) * c(8,6) which translates to the number of ways you can get 4 red balls times the number of ways you can get 6 yellow balls. \n" ); document.write( "that's the numerator. \n" ); document.write( "the number of possible ways to get 10 balls out of 13 balls is c(13,10). \n" ); document.write( "that's the denominator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the second way looks at the probability of getting them in a specified order.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that formula becomes p(4 red and 6 yellow) = 5/13 * 4/12 * 3/11 * 2/10 * 8/9 * 7/8 * 6/7 * 5/6 * 4/5 * 3/4 * c(10,4) = .4895104895.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "on your first draw you pick a red. \n" ); document.write( "the probability of that is 5/13. \n" ); document.write( "on your second draw you pick another red. \n" ); document.write( "the probability of that is 4/12. \n" ); document.write( "ditto until you pick the 4th ball as red. \n" ); document.write( "starting from the 5th ball you draw, you are not looking at yellow. \n" ); document.write( "probability of the firth ball being yellow is 8/9. \n" ); document.write( "that's because there are 8 yellow balls left out of a total of 9 left. \n" ); document.write( "this continues until your last draw of a yellow ball whose probability is 3/4. \n" ); document.write( "there are 4 balls left. \n" ); document.write( "they are RYYY \n" ); document.write( "that's because you took our 4 red and 5 yellow for a total of 9 \n" ); document.write( "13 minus 9 = 4 balls left \n" ); document.write( "5 red minus 4 red = 1 red left \n" ); document.write( "8 yellow minus 5 yellow = 3 yellow left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you wind up with 10 balls that were picked in a certain order. \n" ); document.write( "the number of ways those 10 could be ordered is c(10,4). \n" ); document.write( "that's the number of possible ways you can arrange 4 red balls from 10 total balls. \n" ); document.write( "the other number of ways those 10 could be ordered is c(10,6). \n" ); document.write( "that's the number of possible ways you can arrange 6 yellow balls from 10 total balls. \n" ); document.write( "c(10,4) = 210 \n" ); document.write( "c(10,6) also = 210.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "two different ways get you the same answer which at least confirms the ways are consistent.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to see how each formula works, you can work a different problems where the numbers are small enough that you can show each possible say separately. \n" ); document.write( "i did that with this problem and it confirms both methods are good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution is that the probability is equal to .4895104895.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "round that to 3 decimal places to get .490 which is the same as .49. \n" ); document.write( "even though .49 is the same as .490, you should probably show it as .490 just to indicate that you rounded to 3 decimal places, and not 2.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |