document.write( "Question 1206271: ​Betsy, a recent​ retiree, requires ​$6,000 per year in extra income. She has ​$50,000 to invest and can invest in​ B-rated bonds paying 17​% per year or in a certificate of deposit​ (CD) paying 7​% per year. How much money should be invested in each to realize exactly ​$6,000 in interest per​ year? \n" ); document.write( "
Algebra.Com's Answer #843602 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "x = amount invested in bonds
\n" ); document.write( "50000 - x = amount invested in the CD\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "0.17x + 0.07(50000 - x) = 6000
\n" ); document.write( "is the equation to form.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "This is because,
\n" ); document.write( "0.17x = amount earned from the bonds
\n" ); document.write( "0.07*(50000-x) = amount earned from the bonds
\n" ); document.write( "this is over a 1 year time span\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's solve for x.
\n" ); document.write( "0.17x + 0.07(50000 - x) = 6000
\n" ); document.write( "0.17x + 0.07(50000) + 0.07(-x) = 6000
\n" ); document.write( "0.17x + 3500 -0.07x = 6000
\n" ); document.write( "0.10x + 3500 = 6000
\n" ); document.write( "0.10x = 6000 - 3500
\n" ); document.write( "0.10x = 2500
\n" ); document.write( "x = 2500/0.10
\n" ); document.write( "x = $25,000 must be invested in bonds.
\n" ); document.write( "The other $25,000 would be invested in the CD.
\n" ); document.write( " \n" ); document.write( "
\n" );