document.write( "Question 1206219: You can afford a $300 per month car payment. You've found a 5 year loan at 8% interest.
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document.write( "What the maximum loan could be?\r
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Algebra.Com's Answer #843512 by math_tutor2020(3816)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: $14,795.53\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Monthly payment formula \n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) ) \n" ); document.write( "where, \n" ); document.write( "P = monthly payment \n" ); document.write( "L = loan amount \n" ); document.write( "i = monthly interest rate in decimal form \n" ); document.write( "n = number of months\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We will plug in: \n" ); document.write( "P = 300 \n" ); document.write( "i = 0.08/12 = 0.006666667 approximately \n" ); document.write( "n = 60 (since 5 years = 5*12 = 60 months)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) ) \n" ); document.write( "300 = (L*0.006666667)/( 1-(1+0.006666667)^(-60) ) \n" ); document.write( "300 = L*0.020276394 \n" ); document.write( "L = 300/0.020276394 \n" ); document.write( "L = 14795.53021114 \n" ); document.write( "L = $14,795.53 \n" ); document.write( "Each decimal value is approximate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can use an online calculator such as this to confirm. \n" ); document.write( "https://www.omnicalculator.com/finance/auto-loan \n" ); document.write( "Type 8 into the interest rate box, 5 into the year box, and 300 into the monthly payment box. \n" ); document.write( "After entering those inputs, the \"loan amount\" box will go from empty to $14,795.53 \n" ); document.write( " \n" ); document.write( " |