document.write( "Question 1206219: You can afford a $300 per month car payment. You've found a 5 year loan at 8% interest.
\n" ); document.write( "What the maximum loan could be?\r
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Algebra.Com's Answer #843512 by math_tutor2020(3816)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Answer: $14,795.53\r
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\n" ); document.write( "\n" ); document.write( "Explanation\r
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\n" ); document.write( "\n" ); document.write( "Monthly payment formula
\n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) )
\n" ); document.write( "where,
\n" ); document.write( "P = monthly payment
\n" ); document.write( "L = loan amount
\n" ); document.write( "i = monthly interest rate in decimal form
\n" ); document.write( "n = number of months\r
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\n" ); document.write( "\n" ); document.write( "We will plug in:
\n" ); document.write( "P = 300
\n" ); document.write( "i = 0.08/12 = 0.006666667 approximately
\n" ); document.write( "n = 60 (since 5 years = 5*12 = 60 months)\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) )
\n" ); document.write( "300 = (L*0.006666667)/( 1-(1+0.006666667)^(-60) )
\n" ); document.write( "300 = L*0.020276394
\n" ); document.write( "L = 300/0.020276394
\n" ); document.write( "L = 14795.53021114
\n" ); document.write( "L = $14,795.53
\n" ); document.write( "Each decimal value is approximate.\r
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\n" ); document.write( "\n" ); document.write( "You can use an online calculator such as this to confirm.
\n" ); document.write( "https://www.omnicalculator.com/finance/auto-loan
\n" ); document.write( "Type 8 into the interest rate box, 5 into the year box, and 300 into the monthly payment box.
\n" ); document.write( "After entering those inputs, the \"loan amount\" box will go from empty to $14,795.53
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