document.write( "Question 1206191: we burn 345 calories hiking in 45 min. preparing for a 6 hr hike with special beverage it gives 310 calories replace 1/3 of the calories burned carrying the least packs how many packs do i take
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Algebra.Com's Answer #843461 by Theo(13342)![]() ![]() You can put this solution on YOUR website! you burn 345 calories hiking for 45 minutes. \n" ); document.write( "assuming the calorie burn rate is the same throughout any longer hike, then you are turning calories at the rate of 345/45 calories per minute.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you are hiking for 6 hours, then you will burn 345/45 calories per minute for 6 * 60 = 360 minutes. \n" ); document.write( "the total number of calories consumed would be 345/45 per minute for 360 minutes = 2760 calories.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the special beverage gives you 310 calories per pack, and you want to replace all of the calories consumed, then you would need to take 2760 / 310 = 9 packs of beverage.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you only want to replace 1/3 of the calories consumed, then you would need to take (2760 / 3) / 310 = 3 packs of beverage.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9 packs of beverage would give you 310 * 9 = 2790 calories, which is more than the 2760 consumed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 packs of beverage would give you 310 * 3 = 930 calories, which is more than the 2760/3 = 920 calories consumed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let me know if you have any questions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "theo \n" ); document.write( " \n" ); document.write( " |