document.write( "Question 1206161: A two digit number is such that it's product is 12 and when the digits are reversed the number exceeds the original number by 9, what is the original number? \n" ); document.write( "
Algebra.Com's Answer #843420 by josgarithmetic(39617)\"\" \"About 
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\"10t%2Bu\", the number\r
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\n" ); document.write( "\n" ); document.write( "\"...its product is 12...\";
\n" ); document.write( "product of its two digits?\r
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\n" ); document.write( "\n" ); document.write( "\"tu=12\"\r
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\n" ); document.write( "\n" ); document.write( "The digits reversed...
\n" ); document.write( "\"t%2B10u-%2810t%2Bu%29=9\"\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"-9t%2B9u=9\"
\n" ); document.write( "\"-t%2Bu=1\"
\n" ); document.write( "\"highlight_green%28u=t%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Back to the product of the digits,
\n" ); document.write( "\"t%28t%2B1%29=12\"
\n" ); document.write( "\"3%2A4=12\"-----because only need simple factoring
\n" ); document.write( "\"highlight_green%28t=3%29\"\r
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\n" ); document.write( "\n" ); document.write( "The original number, \"highlight%2834%29\"
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