document.write( "Question 1206158: Hi
\n" ); document.write( "A football team played 38 games for a total of 70 points. 3 points for a win 1 point for a draw, no points for lost games. The team won twice as many games as they drew. How many games were lost.
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Algebra.Com's Answer #843406 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "An informal solution (good mental exercise!!)....

\n" ); document.write( "They won twice as many games as they drew.
\n" ); document.write( "For each \"group\" of two wins and one draw, they earned 2(3)+1(1) = 6+1 = 7 points.
\n" ); document.write( "All together, they earned 70 points; the number of those \"groups\" must have been 70/7 = 10.
\n" ); document.write( "So they must have won 10*2 = 20 games and drawn 10*1 = 10 games.
\n" ); document.write( "That's a total of 20+10 = 30 games in which they earned points.
\n" ); document.write( "Since the total number games was 38, the number of games they lost was 38-30 = 8.

\n" ); document.write( "ANSWER: 8

\n" ); document.write( "The EXACT same solution, formally....

\n" ); document.write( "let x = # of games they drew
\n" ); document.write( "then 2x = # of games they won

\n" ); document.write( "At 3 points for each win and 1 point for each draw (and 0 points for each loss), they earned a total of 70 points:

\n" ); document.write( "\"2x%283%29%2Bx%281%29=70\"
\n" ); document.write( "\"6x%2Bx=70\"
\n" ); document.write( "\"7x=70\"
\n" ); document.write( "\"x=70%2F7=10\"

\n" ); document.write( "# of games won: 2x = 2(10) = 20
\n" ); document.write( "# of games drawn: x = 10
\n" ); document.write( "# of games in which they earned points: 20+10 = 30
\n" ); document.write( "# of games they lost: 38-30 = 8

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