document.write( "Question 115868:
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document.write( "the length of a rectangle is 8 meters less than twice its width. if the diagonal of the rectangle is 20 meters find the length and width \n" );
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Algebra.Com's Answer #84338 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=2W-8 \n" ); document.write( "A^2+B^2=C^2 \n" ); document.write( "(2W-8)^2+W^2=20^2 \n" ); document.write( "4W^2-32W+64+W^2=400 \n" ); document.write( "5W^2-32W+64-400=0 \n" ); document.write( "5W^2-32W-336=0 \n" ); document.write( "(5W+28)(W-12)=0 \n" ); document.write( "W-12=0 \n" ); document.write( "W=12 ANSWER FOR THE WIDTH. \n" ); document.write( "L=2*12-8 \n" ); document.write( "L=24-8 \n" ); document.write( "L=16 ANSWER FOR THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "12^2+16^2=20^2 \n" ); document.write( "144+256=400 \n" ); document.write( "400=400\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |