document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=115898>Question 115898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "How much of an alloy that is 20% copper should be mixed with 200 ounces of an alloy that is 50% copper in order to get an alloy that is 30% copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #84333 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=84333\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .5*200+.2X=.3(200+X)<BR>\n" );
document.write( "100+.2X=60+.3X<BR>\n" );
document.write( ".2X-.3X=60-100<BR>\n" );
document.write( "-.1X=-40<BR>\n" );
document.write( "X=-40/-.1<BR>\n" );
document.write( "X=400 OUNCES OF 20% COPPER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( ".5*200+.2*400=.3(200+400)<BR>\n" );
document.write( "100+80=.3*600<BR>\n" );
document.write( "100+80=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );