document.write( "Question 1206015: You want to buy a $238,000 home. You plan to pay 5% as a down payment, and take out a 30 year loan at 5.5% interest for the rest. \r
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document.write( "How much money in interest will you save if you finance for 15 years instead of 30 years? \n" );
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Algebra.Com's Answer #843185 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: $129,619.80\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work Shown\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "home value = $238,000 \n" ); document.write( "down payment = 5% of home value = 0.05*238000 = $11900\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "loan amount = home value - down payment \n" ); document.write( "loan amount = $238,000 - $11,900 \n" ); document.write( "loan amount = $226,100 \n" ); document.write( "Or \n" ); document.write( "loan amount = 95% of home value (since 5% is already paid off) \n" ); document.write( "loan amount = 0.95*($238,000) \n" ); document.write( "loan amount = $226,100\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Monthly payment formula \n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) ) \n" ); document.write( "where, \n" ); document.write( "P = monthly payment \n" ); document.write( "L = loan amount \n" ); document.write( "i = monthly interest rate in decimal form \n" ); document.write( "n = number of months\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In this case, \n" ); document.write( "L = 226100 \n" ); document.write( "i = 0.055/12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you finance for 15 years, aka 15*12 = 180 months, then we'll have n = 180\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Which leads to this monthly payment: \n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) ) \n" ); document.write( "P = (226100*0.055/12)/( 1-(1+0.055/12)^(-180) ) \n" ); document.write( "P = 1847.425690898 \n" ); document.write( "P = 1847.43\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The monthly payment for a 15 year mortgage is $1847.43 \n" ); document.write( "You can use an online calculator such as this to confirm. \n" ); document.write( "https://www.calculatorsoup.com/calculators/financial/loan-calculator.php\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you pay $1847.43 per month for 180 months, then you'll pay back a total of $332,537.40 due to the scratch work 180*1847.43 = 332537.40 \n" ); document.write( "Let A = 332537.40 since we'll refer to this value later.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now let's consider a 30 year mortgage. \n" ); document.write( "This is over a span of 12*30 = 360 months. \n" ); document.write( "We'll have n = 360 but every other input stays the same. \n" ); document.write( "P = (L*i)/( 1-(1+i)^(-n) ) \n" ); document.write( "P = (226100*0.055/12)/( 1-(1+0.055/12)^(-360) ) \n" ); document.write( "P = 1283.770932046 \n" ); document.write( "P = 1283.77\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This time you pay back $1283.77 per month for 360 months. \n" ); document.write( "The total amount paid back is 360*1283.77 = 462157.20 dollars. \n" ); document.write( "Let's call this value B.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract the two results A and B to find how much is saved. \n" ); document.write( "B - A = 462157.20 - 332537.40 = $129,619.80 which is the final answer.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or you can compute the interest for each mortgage length and then subtract those interest values to find out how much is saved. \n" ); document.write( " \n" ); document.write( " |