document.write( "Question 1205894: A and B are running a race. A has an 84 feet head start when they begin running.
\n" ); document.write( "B runs 12 feet while A covers 8 feet. Determine distance A runs before B overtakes A.\r
\n" ); document.write( "\n" ); document.write( "Not sure how to solve. \n" ); document.write( "

Algebra.Com's Answer #843172 by MathTherapy(10552) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "A and B are running a race.  A has an 84 feet head start when they begin running. \r\n" );
document.write( "B runs 12 feet while A covers 8 feet.  Determine distance A runs before B overtakes A.\r\n" );
document.write( "\r\n" );
document.write( "Not sure how to solve.\r\n" );
document.write( "\r\n" );
document.write( "Let distance A travels before being overtaken by B, be D\r\n" );
document.write( "Since A is already 84 feet ahead of B, then distance B travels to overtake A = \"D + 84\" feet\r\n" );
document.write( "Since B's speed is 12 feet, per time period, B's time to get to \"catch-up\" point = \r\n" );
document.write( "Also, since A's speed is 8 feet, per time period, A's time to get to \"catch-up\" point = \r\n" );
document.write( "Because the time they take to get to the catch-up point is the same, we get: \r\n" );
document.write( "                                            2(D + 84) = 3D ----- Multiplying by LCD, 24\r\n" );
document.write( "                                           2D + 2(84) = 3D\r\n" );
document.write( "                                                2(84) = 3D - 2D\r\n" );
document.write( "Distance A travels before being overtaken by B, or

\n" ); document.write( "

\n" );