document.write( "Question 1205999: The perimeter of a rectangle is 220 yards. The length is 56 yards greater than the width. Find the dimensions. \n" ); document.write( "

Algebra.Com's Answer #843151 by ikleyn(52787) $\"\"$ $\"About$

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\n" ); document.write( "The perimeter of a rectangle is 220 yards. The length is 56 yards greater than the width.
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document.write( "    w + L = 220/2\r\n" );
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document.write( "    w + (w+56) = 110\r\n" );
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document.write( "    2w = 110 - 56\r\n" );
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document.write( "    2w = 54\r\n" );
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document.write( "     w = 54/2 = 27.\r\n" );
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document.write( "ANSWER.  The width is 27 yards.  The length is 27+56 = 83 yards.\r\n" );
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