document.write( "Question 1205985: A 133-lb student races upstairs with a vertical height of 5.3 m in 6.5 s to get to a class on the second floor. How much power in watts does the student expend in doing work against gravity? The Answer has to be in Watts. \n" ); document.write( "

Algebra.Com's Answer #843123 by ikleyn(53937) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "A 133-lb student races upstairs with a vertical height of 5.3 m in 6.5 s
\n" ); document.write( "to get to a class on the second floor. How much power in watts does the student expend
\n" ); document.write( "in doing work against gravity? The Answer has to be in Watts.
\n" ); document.write( "~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "(1)  Convert the mass of 133 lbs to kilograms\r\n" );
document.write( "\r\n" );
document.write( "        133 lbs  is  0.453592*133 = 60.328 kilograms.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "(2)  Calculate the work done\r\n" );
document.write( "\r\n" );
document.write( "        work = m*g*h = 60.328 kg * 9.81 kg/s^2 * 5.3 m = 3136.634 joules\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "(3)  Divide the work by the time to determine the power\r\n" );
document.write( "\r\n" );
document.write( "        power =  = 482.56 watts.    ANSWER\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );