document.write( "Question 1205982: One pump can fill a tank with oil in 4 hours. A second pump can fill the same tank in 3 hours. If both pumps are used at the same time, how long will they take to fill the tank?\r
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document.write( "I tried everything but the answer that I had wrote down from my teacher's answer is 12/7 hours \n" );
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Algebra.Com's Answer #843122 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "There are a few approaches we could take. I'll discuss two methods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Method 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's consider a tank that is 12 gallons. \n" ); document.write( "Feel free to pick any positive number you want since it turns out the capacity doesn't matter. \n" ); document.write( "I'm picking 12 because it is the LCM of 3 and 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Pump A fills the 12 gallon tank in 4 hours when working alone. \n" ); document.write( "The unit rate is 12/4 = 3 gallons per hour. \n" ); document.write( "Formula: rate = (amount done)/time\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Pump B fills the 12 gallon tank in 3 hours when working alone. \n" ); document.write( "Unit rate = 12/3 = 4 gallons per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When both pumps work together, neither pump hindering the other, their combined rate is 3+4 = 7 gallons per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then we'll use this formula \n" ); document.write( "time = (amount done)/rate \n" ); document.write( "to determine that 12/7 hours is the amount of time it takes when both pumps work together.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side notes:
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Method 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Pump A does 1 job in 4 hours when working alone. \n" ); document.write( "\"1 job\" is defined in this case as \"filling the entire tank with oil\". \n" ); document.write( "It's unit rate is 1/4 of a job per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Pump B has a unit rate of 1/3 of a job per hour through similar logic.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Combined rate = 1/4 + 1/3 = 3/12 + 4/12 = 7/12 of a job per hour\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = number of hours to do 1 job if both pumps work together \n" ); document.write( "rate*time = amount done \n" ); document.write( "(7/12 of a job per hour)*(x hours) = 1 job \n" ); document.write( "(7/12)x = 1 \n" ); document.write( "x = 12/7 hours \n" ); document.write( " \n" ); document.write( " |