document.write( "Question 1205967: 14. In AKLM K = ¿L, KL-9-40, LM-7x-37, and KM = 3x + 23, find and the measure of each side. \n" ); document.write( "

Algebra.Com's Answer #843092 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "triangle $\"KLM\"$ \r
\n" ); document.write( "\n" ); document.write( " ∠ $\"K\"$ ≅ ∠ $\"L\"$ \r
\n" ); document.write( "\n" ); document.write( "we know that side $\"KM\"$ is opposite angle $\"L\"$ and side $\"ML\"$ is opposite angle $\"K\"$ , then side $\"LM+=KM\"$ \r
\n" ); document.write( "\n" ); document.write( "if\r
\n" ); document.write( "\n" ); document.write( " $\"KL+=+9x+-+40\"$
\n" ); document.write( " $\"LM+=+7x+-+37\"$
\n" ); document.write( " $\"KM+=+3x+%2B+23\"$ \r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( " $\"LM+=KM\"$
\n" ); document.write( " $\"7x+-+37=3x+%2B+23\"$
\n" ); document.write( " $\"7x+-+3x=37+%2B+23\"$
\n" ); document.write( " $\"4x=60\"$
\n" ); document.write( " $\"x=60%2F4\"$
\n" ); document.write( " $\"x=15\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and the measure of each side is\r
\n" ); document.write( "\n" ); document.write( " $\"KL+=+9x+-+40=9%2A15-40=95\"$
\n" ); document.write( " $\"LM+=+7x+-+37=7%2A15-37=68\"$
\n" ); document.write( " $\"KM+=+3x+%2B+23=3%2A15%2B23=68\"$ \r
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