document.write( "Question 1205956: The third term of a g.p is 12 and the first term is 48.find the sum of the first 11 terms \n" ); document.write( "
Algebra.Com's Answer #843081 by mananth(16946)\"\" \"About 
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The third term of a g.p is 12 and the first term is 48.find the sum of the first 11 terms\r
\n" ); document.write( "\n" ); document.write( "let a 1 be the first term,\r
\n" ); document.write( "\n" ); document.write( "r the common ratio,\r
\n" ); document.write( "\n" ); document.write( "n the term number.\r
\n" ); document.write( "\n" ); document.write( "The nth term of GP is tn = ar^(n-1)\r
\n" ); document.write( "\n" ); document.write( "third term of a G P is 12 \r
\n" ); document.write( "\n" ); document.write( "t3 = 12 = 48 * r^2\r
\n" ); document.write( "\n" ); document.write( "12/48 = r^2\r
\n" ); document.write( "\n" ); document.write( "1/4 = r^2\r
\n" ); document.write( "\n" ); document.write( "r = 1/2\r
\n" ); document.write( "\n" ); document.write( "Sn sum of n terms of G P =\"+%28a1%2A%28r%5En+-1%29%29%2F+%28r+-1%29\"\r
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\n" ); document.write( "\n" ); document.write( " S 11 = (48*((1/2)^11 -1))/ ((1/2)-1)}},\r
\n" ); document.write( "\n" ); document.write( "=96 (ROUNDED OFF)\r
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\n" ); document.write( "\n" ); document.write( "the terms are\r
\n" ); document.write( "\n" ); document.write( "48, 24, 12, 6, 3, 3/2, 3/4, 3/8, 3/16, 3/32, 3/64\r
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