document.write( "Question 115740: The length of a rectangle is 7 less than twice the width. the perimeter is 61. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #84301 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=2W-7 \n" ); document.write( "P=2L+2W \n" ); document.write( "61=2(2W-7)+2W \n" ); document.write( "61=4W-14+2W \n" ); document.write( "61=6W-14 \n" ); document.write( "6W=61+14 \n" ); document.write( "6W=75 \n" ); document.write( "W=75/6 \n" ); document.write( "W=12.5 ANSWER FOR THE WIDTH \n" ); document.write( "L=2*12.5-7 \n" ); document.write( "L=25-7 \n" ); document.write( "L=18 ANSWER FOR THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "61=2*12.5+2*18 \n" ); document.write( "61=25+36 \n" ); document.write( "61=61 \n" ); document.write( " \n" ); document.write( " |