document.write( "Question 115740: The length of a rectangle is 7 less than twice the width. the perimeter is 61. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #84301 by checkley71(8403)\"\" \"About 
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L=2W-7
\n" ); document.write( "P=2L+2W
\n" ); document.write( "61=2(2W-7)+2W
\n" ); document.write( "61=4W-14+2W
\n" ); document.write( "61=6W-14
\n" ); document.write( "6W=61+14
\n" ); document.write( "6W=75
\n" ); document.write( "W=75/6
\n" ); document.write( "W=12.5 ANSWER FOR THE WIDTH
\n" ); document.write( "L=2*12.5-7
\n" ); document.write( "L=25-7
\n" ); document.write( "L=18 ANSWER FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "61=2*12.5+2*18
\n" ); document.write( "61=25+36
\n" ); document.write( "61=61
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