document.write( "Question 1205894: A and B are running a race. A has an 84 feet head start when they begin running.
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document.write( "B runs 12 feet while A covers 8 feet. Determine distance A runs before B overtakes A.\r
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document.write( "Not sure how to solve. \n" );
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Algebra.Com's Answer #842997 by greenestamps(13198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(Note to tutor @ikleyn: fix a small error in your response....) \n" ); document.write( "The other tutor shows a perfectly good way to set up and solve the problem. \n" ); document.write( "Here is a very different way to set up and solve the problem. \n" ); document.write( "Over some time interval, B runs 12 feet while A runs 8 feet; in that time interval B runs 4 feet farther than A. \n" ); document.write( "A is 84 feet ahead of B at the start; the number of time intervals needed for B to overtake A is 84/4 = 21. \n" ); document.write( "So the distances the two of them run before B overtakes A are: \n" ); document.write( "A: 21*8 = 168 feet \n" ); document.write( "B: 21*12 = 252 feet \n" ); document.write( "ANSWER: (distance A runs before B overtakes him) 168 feet \n" ); document.write( "That same solution formally.... \n" ); document.write( "Let x be the number of time intervals in which B runs 12 feet and A runs 8 feet. \n" ); document.write( "12x = distance B runs \n" ); document.write( "8x = distance A runs \n" ); document.write( "In overtaking A, B runs 84 feet farther than A: \n" ); document.write( "12x = 8x+84 \n" ); document.write( "4x = 84 \n" ); document.write( "x = 21 \n" ); document.write( "ANSWER: the distance A runs is 8x = 168 feet \n" ); document.write( " \n" ); document.write( " |