document.write( "Question 1205877: Why does the graph of the secant function have breaks in it?\r
\n" ); document.write( "\n" ); document.write( "A. Because the secant function is undefined at 𝝿.
\n" ); document.write( "B. Because the secant function is undefined at 𝝿 and - 𝝿.
\n" ); document.write( "C. Because the secant function is undefined at 0.
\n" ); document.write( "D. Because the secant function is undefined at 90° and -90°
\n" ); document.write( "E. Because the secant function has to reach infinity, which doesn't really exist.
\n" ); document.write( "F. Because the secant function has to have a break in it to be a function.
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Algebra.Com's Answer #842950 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The secant function was defined by the reciprocal identity\r
\n" ); document.write( "\n" ); document.write( "sec(x)=1/cos(x)\r
\n" ); document.write( "\n" ); document.write( "the secant function is \"undefined\" when the cosine is \"+0\", leading to vertical asymptotes at \"pi%2F2\", \"+3pi%2F2\", etc\r
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\n" ); document.write( "\n" ); document.write( "\"pi%2F2+=+90\"°
\n" ); document.write( "\"+3pi%2F2=-90\"°\r
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\n" ); document.write( "\n" ); document.write( "answer:
\n" ); document.write( "D. Because the secant function is undefined at \"90\"° and \"-90\"°\r
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