document.write( "Question 1205850: Bought service vehicle worth 200,000; paid 40% cash, while the balance in 4 equal monthly installments with 2% interest per month.\r
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Algebra.Com's Answer #842906 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
40% of 200,000 was paid in cash.
\n" ); document.write( "that left 60% to be financed.
\n" ); document.write( "200,000 * .6 = 120,000 that was financed.
\n" ); document.write( "this was to be paid in 4 equal monthly installments with 2% interest rate per month.\r
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\n" ); document.write( "\n" ); document.write( "the financial calculator at C:\Users\dtheo\Pictures\G27.1041.53.jpg can be used to solve this.\r
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\n" ); document.write( "\n" ); document.write( "there are formulas you can use as well, but the calculator is much easier and uses the same formulas.
\n" ); document.write( "if you need to use formulas, let me know and i'll send you the appropriate formula for this problem.\r
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\n" ); document.write( "\n" ); document.write( "i used the calculator and came up with the following results.\r
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\n" ); document.write( "\n" ); document.write( "the payment at the end of each month was 31,514.85.\r
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\n" ); document.write( "\n" ); document.write( "there were 4 payments for a total payment of 126,059.4.\r
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\n" ); document.write( "\n" ); document.write( "since the amount due was 120,000, then the difference was the interest on the loan.\r
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\n" ); document.write( "\n" ); document.write( "that was equal to 6,059.4.\r
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\n" ); document.write( "\n" ); document.write( "since the number of payments was small, you could actually calculate what happened month by month.\r
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\n" ); document.write( "\n" ); document.write( "it works like this.
\n" ); document.write( "the amount of the loan was 120000
\n" ); document.write( "the payment at the end of each month was 31514.85 rounded to the nearest penny.\r
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\n" ); document.write( "\n" ); document.write( "at the end of the first month, the amount owed became 120000 * 1.02 = 122400.
\n" ); document.write( "the payment was subtracted from that to get a remaining balance of 90885.15.\r
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\n" ); document.write( "\n" ); document.write( "at the end of the second month, the amount owed became 90885.15 * 1.02 = 92702.853.
\n" ); document.write( "the payment was subtracted from that to get a remaining balance of 61188.003.\r
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\n" ); document.write( "\n" ); document.write( "at the end of the third month, the amount owed became 61188.003 * 1.02 = 62411.76306.
\n" ); document.write( "the payment was subtracted from that to get a remaining balance of 30896.91306.\r
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\n" ); document.write( "\n" ); document.write( "at the end of the fourth month, the amount owed became 30896.91306 * 1.02 = 31514.85132.
\n" ); document.write( "the payment was subtracted from that to get a remaining balance of .0013212.\r
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\n" ); document.write( "\n" ); document.write( "without rounding of intermediate results, that amount would have been 0.
\n" ); document.write( "in fact, if you round the remaining balance to 2 decimal places, it becomes 0.\r
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\n" ); document.write( "\n" ); document.write( "the total number of payments was 4.
\n" ); document.write( "31,514.85 * 4 = 126,059.40.
\n" ); document.write( "since the loan was for 120,000, then the interest paid was 6,059.40.\r
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\n" ); document.write( "\n" ); document.write( "that's your solution.\r
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\n" ); document.write( "\n" ); document.write( "here's what the calculator results look like.\r
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\n" ); document.write( "\n" ); document.write( "inputs are everything except payment.
\n" ); document.write( "output is payment.\r
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