document.write( "Question 115826: Use the method of substitution to solve the system of linear equations
\n" ); document.write( "a) x-y=8
\n" ); document.write( " x-y=-2\r
\n" ); document.write( "\n" ); document.write( "b) 2x+y=5
\n" ); document.write( " 4x-3y=15
\n" ); document.write( "

Algebra.Com's Answer #84290 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "a)
\n" ); document.write( "\"x-y=8\"
\n" ); document.write( "\"x-y=-2\"\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cx+%2B+-1%5Cy+=+8%2C%0D%0A++++1%5Cx+%2B+-1%5Cy+=+-2+%29%0D%0A++\"We'll use substitution. After moving -1*y to the right, we get:
\n" ); document.write( " \"1%2Ax+=+8+-+-1%2Ay\", or \"x+=+8%2F1+-+-1%2Ay%2F1\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"1%2A%288%2F1+-+-1%2Ay%2F1%29+%2B+-1%5Cy+=+-2\" and simplify: So, we know that y=10=0. Since \"x+=+8%2F1+-+-1%2Ay%2F1\", x=18.
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\n" ); document.write( " Answer: \"system%28+x=18%2C+y=10=0+%29\".
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\n" ); document.write( "\n" ); document.write( "b)
\n" ); document.write( "\"2x%2By=5\"
\n" ); document.write( " \"4x-3y=15\"\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++2%5Cx+%2B+1%5Cy+=+5%2C%0D%0A++++4%5Cx+%2B+-3%5Cy+=+15+%29%0D%0A++\"We'll use substitution. After moving 1*y to the right, we get:
\n" ); document.write( " \"2%2Ax+=+5+-+1%2Ay\", or \"x+=+5%2F2+-+1%2Ay%2F2\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"4%2A%285%2F2+-+1%2Ay%2F2%29+%2B+-3%5Cy+=+15\" and simplify: So, we know that y=-1. Since \"x+=+5%2F2+-+1%2Ay%2F2\", x=3.
\n" ); document.write( "
\n" ); document.write( " Answer: \"system%28+x=3%2C+y=-1+%29\".
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