document.write( "Question 1205782: Each Filipino uses an average of 650 pounds of plastic in a year. Suppose that the distribution is approximately normal with a population standard deviation of 153.5 pounds. Assume the variable is normally distributed. Find the probability that a randomly selected Filipino uses \r
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document.write( "a.) More than 800 pounds of paper in a year (10 points)\r
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document.write( "b.) Less than 400 pounds a year (10 points)\r
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document.write( "c.) Between 500 and 700 pounds a year (10 points)\r
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Algebra.Com's Answer #842876 by Theo(13342)![]() ![]() You can put this solution on YOUR website! population mean is 650 and population standard deviation is 153.5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z-score formula is z = (x-m)/s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in this problem:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is the value of the randomly selected variable. \n" ); document.write( "m is the population mean \n" ); document.write( "s is the standard deviation. \n" ); document.write( "z is the z-score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "answers to your questions are shown below.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find the probability that a randomly selected Filipino uses\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a.) More than 800 pounds of paper in a year (10 points)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for x = 800, z = (800 - 650) / 153.5 = .9771986971.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area to the right of this z-score is equal to .1642. \n" ); document.write( "that's the probability that a random selected filipino uses more than 800 pounds of plastic in a year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b.) Less than 400 pounds a year (10 points)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for x = 400, z = (400 - 650) / 153.5 = -1.628664495.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area to the left of this z-score is equal to .0517. \n" ); document.write( "that's the probability that a randomly selected filipino uses less than 400 pounds of plastic in a year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c.) Between 500 and 700 pounds a year (10 points)\r \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( "for x = 500, z = (500 - 650) / 153.5 = -.9771986971. \n" ); document.write( "for x = 700, z = (700 - 650) / 153.5 = .325732899.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "area in between these two z-score is equal to .4635. \n" ); document.write( "that's the probability that a randomly selected filipino uses between 500 and 700 pounds of plastic in a year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "calculator used can be found at https://davidmlane.com/hyperstat/z_table.html\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |