document.write( "Question 1205779: There were 5c 10c and 20c coins in Joel's wallet in the ratio of 2:6:7 respectively. If he takes out half the number of 5c and half the number of 10c coins they would make up $4.20
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Algebra.Com's Answer #842831 by ikleyn(52797)\"\" \"About 
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\n" ); document.write( "There are 5c, 10c, and 20c coins in Joel's wallet in the ratio of 2:6:7 respectively.
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document.write( "According to the problem, there are 2x of 5c coins; 6x of 10c coins and 7x of 20c coins,\r\n" );
document.write( "where x is the common measure of these different quantities.\r\n" );
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document.write( "Half of 2x 5c coins is x 5c coins; half of 6x 10c coins is 3x 10c coins.\r\n" );
document.write( "Their total is $4.20, or 420 cents\r\n" );
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document.write( "    5x + 10(3x) = 420  cents.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    5x + 30x = 420\r\n" );
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document.write( "      35x    = 420\r\n" );
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document.write( "        x    = 420/35 = 12.\r\n" );
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document.write( "Now we are in position to answer the problem's questions.\r\n" );
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document.write( "(a)  The number of 20c coins in his wallet is 7x = 7*12 = 84.\r\n" );
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document.write( "(b)  The total money in his wallet is  5*(2x) + 10*(6x) + 20*(7x) = 5*(2*12) + 10*(6*12) + 20*(7*12) = 2520 cents or $25.20.\r\n" );
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