document.write( "Question 1205778: Hi, I have shown my working for the question below, am I on the right track?\r
\n" ); document.write( "\n" ); document.write( "〖Simplify 10〗^241 mod(13) \r
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\n" ); document.write( "\n" ); document.write( "Fermat’s Little Theorem states:
\n" ); document.write( "a^(p-1)≡1mod(p)\r
\n" ); document.write( "\n" ); document.write( "Substitute:
\n" ); document.write( "10^12≡1mod(13) \r
\n" ); document.write( "\n" ); document.write( "By our multiplication theorem we know that if
\n" ); document.write( "10^12≡1mod(13)
\n" ); document.write( "Then
\n" ); document.write( "10^((12)A)≡(1)^A mod (13) \r
\n" ); document.write( "\n" ); document.write( "We want to get from a power of 12 up to around 241, and 12 x 20 = 240
\n" ); document.write( " 10^(12)(20) ≡1^20 mod(13)
\n" ); document.write( " ≡1mod(13)\r
\n" ); document.write( "\n" ); document.write( "So what we have so far is
\n" ); document.write( "10^241 mod(13)≡10^240×10^1 mod(13)
\n" ); document.write( " ≡1×10mod(13)
\n" ); document.write( " ≡10mod(13)\r
\n" ); document.write( "\n" ); document.write( "When 10^241is divided by 13, the remainder is 10 \r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #842809 by ikleyn(52788)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Your logic and your reasoning are correct.\r
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\n" ); document.write( "\n" ); document.write( "Your solution and your answer are correct.\r
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\n" ); document.write( "\n" ); document.write( "Nice job.\r
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\n" ); document.write( "\n" ); document.write( "My congratulations.\r
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