document.write( "Question 1205775: Modern oil tankers weigh over a half-million tons and have lengths of up to one-fourth mile. Such massive ships require a distance of 4.3 km (about 2.7 mi) and a time of 16 min to come to a stop from a top speed of 32 km/h.
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Algebra.Com's Answer #842804 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "Modern oil tankers weigh over a half-million tons and have lengths of up to one-fourth mile.
\n" ); document.write( "Such massive ships require a distance of 4.3 km (about 2.7 mi) and a time of 16 min
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\n" ); document.write( "(b) What is the magnitude of the ship's average velocity in m/s?
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document.write( "(a)  This motion is uniform deceleration with constant deceleration.\r\n" );
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document.write( "     Let \"a\" be the value of the constant deceleration.\r\n" );
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document.write( "     From Physics (Mechanics and Kinematics), having given the initial speed of 32 km/h\r\n" );
document.write( "     and time 16 minutes to stop, we can calculate the average deceleration\r\n" );
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document.write( "         a = \"32%2F%28%2816%2F60%29%29\" = \"%2832%2A60%29%2F16\" = 2*60 = 120 km/h^2.\r\n" );
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document.write( "     Here the ratio \"16%2F60\" is the time of 16 minutes converted to hours.\r\n" );
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document.write( "     Converted to m/s^2, this value of 120 km/h^2 is  \r\n" );
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document.write( "         \"%28120%2A1000%29%2F%283600%2A3600%29\" = \"12%2F%2836%2A36%29\" = \"1%2F%283%2A36%29\" = \"1%2F108\" m/s^2 = 0.00926 m/s^2  (rounded).\r\n" );
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document.write( "     This value  0.00926 m/s^2 is the answer (average deceleration in m/s^2) for part (a).\r\n" );
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document.write( "(b)  The speed is linear function of time in this motion.\r\n" );
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document.write( "     The maximum value of the speed is 32 km/h; the minimum value is 0 km/h, when the ship stops.\r\n" );
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document.write( "     The magnitude of the ship's average velocity in km/h is  \"32%2F2\" = 16 km/h,\r\n" );
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document.write( "     or  \"%2816%2A1000%29%2F3600\" m/s = \"16000%2F3600\" m/s = \"160%2F36\" = \"40%2F9\" m/s = 4\"4%2F9\" m/s = 4.44444 m/s (rounded).\r\n" );
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document.write( "     This value  4\"4%2F9\" = 4.44444 m/s is the answer (ship's average speed in m/s) for part (b).\r\n" );
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