document.write( "Question 1205736: The largest sphere that will fit is placed inside a cone with base radius 𝑟
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Algebra.Com's Answer #842798 by Edwin McCravy(20064)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "First we look at the mid cross section.\r\n" );
document.write( "Let the radius of the circle (which is also the radius of the sphere),\r\n" );
document.write( "be \"a\".\r\n" );
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document.write( "Then the ratio of the volume of the sphere to the volume of the cone,\r\n" );
document.write( "which is the answer you're looking for, will be\r\n" );
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document.write( "\"ratio\"\"%22%22=%22%22\"\"%28expr%284%2F3%29pi%2Aa%5E3%29%2F%28expr%281%2F3%29pi%2Ar%5E2%2Ah%29\"\"%22%22=%22%22\"\"4a%5E3%2F%28r%5E2%2Ah%29\"\r\n" );
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document.write( "The hard part is finding the radius of the sphere \"a\", in terms\r\n" );
document.write( "of \"r\" and \"h\".\r\n" );
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document.write( "By similar right triangles OPQ and TSQ,\r\n" );
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document.write( "\"OP%2FOQ=+TS%2FTQ\"\r\n" );
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document.write( "SQ = h\r\n" );
document.write( "SO = a\r\n" );
document.write( "OQ = SQ-SO = h-a\r\n" );
document.write( "OP = a\r\n" );
document.write( "TS = r\r\n" );
document.write( "\"TQ=sqrt%28TS%5E2%2BSQ%5E2%29\"\"%22%22=%22%22\"\"sqrt%28r%5E2%2Bh%5E2%29\"\r\n" );
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document.write( "Substituting,\r\n" );
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document.write( "\"a%5E%22%22%2F%28h-a%5E%22%22%29\"\"%22%22=%22%22\"\"r%5E%22%22%2Fsqrt%28r%5E2%2Bh%5E2%29\" \r\n" );
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document.write( "Cross-multiplying:\r\n" );
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document.write( "\"a%2Asqrt%28r%5E2%2Bh%5E2%29\"\"%22%22=%22%22\"\"r%28h-a%29\"  \r\n" );
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document.write( "\"a%2Asqrt%28r%5E2%2Bh%5E2%29\"\"%22%22=%22%22\"\"rh-ra\" \r\n" );
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document.write( "\"a%2Asqrt%28r%5E2%2Bh%5E2%29%2Bra\"\"%22%22=%22%22\"\"rh\"\r\n" );
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document.write( "\"a%28sqrt%28r%5E2%2Bh%5E2%29%2Br%29\"\"%22%22=%22%22\"\"rh\"\r\n" );
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document.write( "\"a\"\"%22%22=%22%22\"\"%28rh%29%2F%28sqrt%28r%5E2%2Bh%5E2%29%2Br%29\"\r\n" );
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document.write( "Now we substitute that horrible thing in: \r\n" );
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document.write( "\"ratio\"\"%22%22=%22%22\"\"4a%5E3%2F%28r%5E2%2Ah%29\"\r\n" );
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document.write( "\"ratio\"\"%22%22=%22%22\"\"4%28%28rh%29%2F%28sqrt%28r%5E2%2Bh%5E2%29%2Br%29%29%5E3%2F%28r%5E2%2Ah%29\"\"%22%22=%22%22\"\"expr%284%2F%28r%5E2%2Ah%29%29+%0D%0A%28%28rh%29%2F%28sqrt%28r%5E2%2Bh%5E2%29%2Br%29%29%5E3\"\"%22%22=%22%22\"\"expr%284%2F%28r%5E2%2Ah%29%29+%28r%5E3h%5E3%29%2F%28sqrt%28r%5E2%2Bh%5E2%29%2Br%29%5E3\"\"%22%22=%22%22\"\"%284r%2Ah%5E2%29%2F%28sqrt%28r%5E2%2Bh%5E2%29%2Br%29%5E3\"\r\n" );
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document.write( "Edwin
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