document.write( "Question 1205725: So, my problem is this I solved it once and I got it wrong can you guys help me out?
\n" ); document.write( "8x-6y=-2
\n" ); document.write( "8x+5y=-13\r
\n" ); document.write( "\n" ); document.write( "I am supposed to use the elimination method and get an ordered pair and I am still confused. \n" ); document.write( "

Algebra.Com's Answer #842788 by MathTherapy(10552) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "So, my problem is this I solved it once and I got it wrong can you guys help me out?\r\n" );
document.write( "8x-6y=-2\r\n" );
document.write( "8x+5y=-13\r\n" );
document.write( "\r\n" );
document.write( "I am supposed to use the elimination method and get an ordered pair and I am still confused.\r\n" );
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document.write( "8x - 6y = - 2 ------ eq (i)\r\n" );
document.write( "8x + 5y = -13 ------ eq (ii)\r\n" );
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document.write( "Notice that both equations have IDENTICAL x variables. In order to ELIMINATE ths x-variable and\r\n" );
document.write( "solve for the other variable (y, in this case), we need to either SUBTRACT eq (i) from eq (ii),\r\n" );
document.write( "or vice-versa. I chose to do the former.\r\n" );
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document.write( "          8x - 6y = - 2 ------ eq (i)\r\n" );
document.write( "          8x + 5y = - 13 ----- eq (ii)\r\n" );
document.write( "              11y = - 11 ----- Subtracting eq (i) from eq (ii)\r\n" );
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document.write( "Now, substitute - 1 for y in either eq (i) or eq (ii). Again, I chose the former.\r\n" );
document.write( "          8x - 6y = - 2 ------ eq (i)\r\n" );
document.write( "      8x - 6(- 1) = - 2  ----- Substituting - 1 for y in eq (i)\r\n" );
document.write( "           8x + 6 = - 2\r\n" );
document.write( "               8x = - 8\r\n" );
document.write( "              \r\n" );
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document.write( "              Finito!!

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