document.write( "Question 1205762: Find the dimension of a rectangle that will yield the maximum area of its perimeter is 54 meters. What is the maximum area? \n" ); document.write( "
Algebra.Com's Answer #842779 by Edwin McCravy(20064)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Solve the first equation for L (Note: you could have solved it for W)\r\n" );
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document.write( "\"2L=54-2W\"\r\n" );
document.write( "\"L=27-W\"\r\n" );
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document.write( "Substitute in \r\n" );
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document.write( "\"A=%2827-W%29W\"\r\n" );
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document.write( "Use the product rule to differentiate with respect to W\r\n" );
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document.write( "\"dA%2FdW=%2827-W%29%281%29%2BW%28-1%29\"\r\n" );
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document.write( "\"dA%2FdW=27-W-W\"\r\n" );
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document.write( "\"dA%2FdW=27-2W\"\r\n" );
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document.write( "Se the derivative = 0, find maxima and minima\r\n" );
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document.write( "\"27-2W=0\"\r\n" );
document.write( "\"27=2W\"\r\n" );
document.write( "\"27%2F2=W\"\r\n" );
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document.write( "Substitute in\r\n" );
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document.write( "\"L=27-W\"\r\n" );
document.write( "\"L=27-27%2F2\"\r\n" );
document.write( "\"L=27%2Aexpr%282%2F2%29-27%2F2\"\r\n" );
document.write( "\"L=54%2F2-27%2F2\"\r\n" );
document.write( "\"L=27%2F2\"\r\n" );
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document.write( "Whaddyaknow? The length and width are both the same.\r\n" );
document.write( "27/2 meters = 13.5 meters each. What kind of rectangle \r\n" );
document.write( "is that?\r\n" );
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document.write( "\"A=LW\"\r\n" );
document.write( "\"A=expr%2827%2F2%29expr%2827%2F2%29\"\r\n" );
document.write( "\"A=729%2F4=182.25\"\r\n" );
document.write( "The maximum area is 182.25 square meters.\r\n" );
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document.write( "Edwin

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