document.write( "Question 1205749: The number of people, y, in tens of thousands, who reported birdwatching as a hobby between 2013 and 2020 is modeled by the equation y=2x^2-16x+150, where x
\n" ); document.write( " is the number of years since 2013. Select the years when the number of people who reported birdwatching as a hobby was 126 ten thousand.\r
\n" ); document.write( "\n" ); document.write( "2013\r
\n" ); document.write( "\n" ); document.write( "2014\r
\n" ); document.write( "\n" ); document.write( "2015\r
\n" ); document.write( "\n" ); document.write( "2016\r
\n" ); document.write( "\n" ); document.write( "2017\r
\n" ); document.write( "\n" ); document.write( "2018\r
\n" ); document.write( "\n" ); document.write( "2019\r
\n" ); document.write( "\n" ); document.write( "2020
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\n" ); document.write( "

Algebra.Com's Answer #842768 by josgarithmetic(39616)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "YEAR      x VALUE\r\n" );
document.write( "2013        0\r\n" );
document.write( "2014        1\r\n" );
document.write( "2015        2\r\n" );
document.write( "2016        3\r\n" );
document.write( "2017        4\r\n" );
document.write( "2018        5\r\n" );
document.write( "2019        6\r\n" );
document.write( "2020        7\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "\"126=2x%5E2-16x%2B150\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--
\n" ); document.write( "--\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-8x%2B75=63\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-8x%2B12=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%28x-6%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"system%28x=2%2C+AND%2C+x=6%29\"\r
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\n" ); document.write( "\n" ); document.write( "The years 2015 and 2019
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