document.write( "Question 1205749: The number of people, y, in tens of thousands, who reported birdwatching as a hobby between 2013 and 2020 is modeled by the equation y=2x^2-16x+150, where x
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document.write( " is the number of years since 2013. Select the years when the number of people who reported birdwatching as a hobby was 126 ten thousand.\r
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document.write( "2013\r
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document.write( "2014\r
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document.write( "2015\r
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document.write( "2016\r
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document.write( "2017\r
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document.write( "2018\r
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document.write( "2019\r
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document.write( "2020
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document.write( "
Algebra.Com's Answer #842768 by josgarithmetic(39616)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "YEAR x VALUE\r\n" ); document.write( "2013 0\r\n" ); document.write( "2014 1\r\n" ); document.write( "2015 2\r\n" ); document.write( "2016 3\r\n" ); document.write( "2017 4\r\n" ); document.write( "2018 5\r\n" ); document.write( "2019 6\r\n" ); document.write( "2020 7\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-- \n" ); document.write( "--\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The years 2015 and 2019 \n" ); document.write( " |