document.write( "Question 1205740: 36x+54y=450 12x+15y=135 \n" ); document.write( "
Algebra.Com's Answer #842747 by Theo(13342)![]() ![]() You can put this solution on YOUR website! 36x + 54y = 450 \n" ); document.write( "12x + 15y = 135\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "leave first equation as is and multiply second equation by 3 to get: \n" ); document.write( "36x + 54y = 450 \n" ); document.write( "36x + 45y = 405\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract second equation from first to get: \n" ); document.write( "9y = 45\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for y to get: \n" ); document.write( "y = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace y with 5 in first equation and solve for x to get: \n" ); document.write( "36x + 54y = 450 becomes 36x + 54 * 5 = 450 which becomes 36x + 270 = 450.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 270 from both sides of the equation to get: \n" ); document.write( "36x = 450 - 270\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get: \n" ); document.write( "36x = 180\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get: \n" ); document.write( "x = 180/36 = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace x with 5 and y with 5 in the second original equation to get: \n" ); document.write( "12x + 15y = 135 becomes 12 * 5 + 15 * 5 = 135 which becopmes: \n" ); document.write( "60 + 75 = 135 which becomes 135 = 135.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this confirms the values of x = 5 and y = 5 satisfies both original equations. \n" ); document.write( "that's your solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |