document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1205731>Question 1205731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 50 coins in dimes and quarters have a total value of $11.00. How many dimes and quarters are there? </SPAN>\n" );
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document.write( "Informally....<br><BR>\n" );
document.write( "If all 50 coins were dimes, the total value would be $5.00.<BR>\n" );
document.write( "The actual total value is $11.00, which is $6.00 more.<BR>\n" );
document.write( "Since each quarter is worth $0.15 more than each dime, the number of quarters must be $6.00/$0.15 = 600/15 = 40.<br><BR>\n" );
document.write( "ANSWER: 40 quarters and 10 dimes<br><BR>\n" );
document.write( "CHECK: 40($0.25)+10($0.10) = $10.00+$1.00 = $11.00<br><BR>\n" );
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document.write( "And here is a really unorthodox solution, treating the problem as a mixture problem.<br><BR>\n" );
document.write( "You are mixing quarters worth 25 cents each with dimes worth 10 cents each to get a mixture of coins worth an average of $11.00/50 = 22 cents each.<BR>\n" );
document.write( "Since 22 cents is 4/5 of the way from 10 cents to 25 cents, 4/5 of the coins must be quarters.  (From 10 to 25 is a difference of 15; from 10 to 22 is a difference of 12; 12/15 = 4/5.)<BR>\n" );
document.write( "4/5 of 50 is 40.<br><BR>\n" );
document.write( "ANSWER (again, of course): 40 quarters and 10 dimes<br><BR>\n" );
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